Post by account_disabled on Oct 31, 2017 6:19:57 GMT -5
Hi,
I have a question regarding the number of water molecules produced by cellular respiration. At the level of the electron transport system (ETS), the equation regarding O2 as the final electron acceptor is: 1/2O2 + 2é + 2H+ --- H20. Considering that the 10 NADH molecules entering the ETS will contribute to 10 é pairs (and hence to the consumption of 10/2 = 5 O2 molecules), and that the 2 FADH2 molecules entering the ETS will contribute to 2 é pairs (and use 2/2 = 1 O2 molecule). Then what about water? According to this equation, a total of 12 molecules of water would be produced. How should we relate this to the general equation of glucose breakdown: glucose + 6 O2 ---- 6 CO2 + 6 H20 + E This should mean that 6 water molecules are consumed at some other point to account for the global equation??
Please help.
Thanks!
I didn't find the right solution from the Internet.
References www.biology-online.org/biology-forum/about5431.html
animation video
I have a question regarding the number of water molecules produced by cellular respiration. At the level of the electron transport system (ETS), the equation regarding O2 as the final electron acceptor is: 1/2O2 + 2é + 2H+ --- H20. Considering that the 10 NADH molecules entering the ETS will contribute to 10 é pairs (and hence to the consumption of 10/2 = 5 O2 molecules), and that the 2 FADH2 molecules entering the ETS will contribute to 2 é pairs (and use 2/2 = 1 O2 molecule). Then what about water? According to this equation, a total of 12 molecules of water would be produced. How should we relate this to the general equation of glucose breakdown: glucose + 6 O2 ---- 6 CO2 + 6 H20 + E This should mean that 6 water molecules are consumed at some other point to account for the global equation??
Please help.
Thanks!
I didn't find the right solution from the Internet.
References www.biology-online.org/biology-forum/about5431.html
animation video